>> q 0.68 Tc /Matrix [1 0 0 1 0 0] Q endobj /Meta171 185 0 R >> >> 0 g q q >> endstream endobj /Resources<< q /Resources<< q endobj 0 w Q /Matrix [1 0 0 1 0 0] 0.458 0 0 RG /FormType 1 endobj q 1 i /Matrix [1 0 0 1 0 0] /Subtype /Form endstream /Type /XObject stream /Matrix [1 0 0 1 0 0] >> /Length 106 << 0 g endobj Q 11.99 8.18 TD /Length 69 /FormType 1 Q Q << /Resources<< (-4) Tj 1.005 0 0 1.007 102.382 563.103 cm endobj ET 130 0 obj S stream q /Subtype /Form /ProcSet[/PDF] /Meta427 443 0 R /Subtype /Form 0 G /F3 17 0 R /Type /XObject Twice a number decreased by 8 gives 58. /Resources<< 0.737 w /Subtype /Form /Type /XObject q endobj Q q /Matrix [1 0 0 1 0 0] 0.458 0 0 RG /Type /XObject /Type /XObject endstream Q Q /F1 7 0 R /Meta156 Do /Meta109 Do /Length 70 Q >> endstream Q /BBox [0 0 88.214 16.44] endstream 1 i /FormType 1 (A\)) Tj /ProcSet[/PDF/Text] q /Font << /Font << 0.564 G /BBox [0 0 17.177 16.44] 1 g >> q /Meta217 Do 6.746 8.18 TD >> q Q endstream >> endstream endstream q stream /BBox [0 0 534.67 16.44] q >> q /Subtype /Form q /Font << << 0 g /BBox [0 0 534.67 16.44] 1.007 0 0 1.007 130.989 383.934 cm (x) Tj 185.725 5.203 TD /Type /XObject 1 g 672.261 599.991 m 342 0 obj q /Length 68 /FormType 1 /Type /XObject 0.737 w /Font << q stream /FormType 1 /Matrix [1 0 0 1 0 0] q 1 i /Meta43 Do /FormType 1 << endstream /FormType 1 Q (13) Tj 0.458 0 0 RG 90 0 obj /Matrix [1 0 0 1 0 0] 0.369 Tc Q 0.68 Tc /Type /XObject 1.502 5.203 TD << 0.564 G 1 g /Resources<< >> /FormType 1 /BBox [0 0 534.67 16.44] 127 0 obj /Matrix [1 0 0 1 0 0] 1 i 1.005 0 0 1.007 102.382 400.496 cm q /F4 12.131 Tf Q 0.51 Tc 0 g 254 0 obj << (38) Tj 38.948 5.203 TD /Resources<< 1.502 5.203 TD q >> Q /Widths [ 500 0 502]>> q Q q 0.297 Tc /Meta166 180 0 R /Resources<< /FormType 1 [(The )-19(quotient of )] TJ >> BT q (B) Tj endstream 8 0 obj If mario jumps 3 times and luigi jumps 62 times. stream Twice a number when decreased by 7 gives 45. << q /MediaBox [0 0 767.868 993.712] /Meta85 99 0 R 0 G /Font << q endstream /Meta245 259 0 R 0 w /F1 12.131 Tf 0 g q /Type /XObject 0 G /Meta339 353 0 R Q 0 G >> /FormType 1 /F4 36 0 R endobj /F3 17 0 R /F3 12.131 Tf >> Q 0 20.154 m Q /Font << q 549.694 0 0 16.469 0 -0.0283 cm >> /Meta121 Do q q q q /Type /XObject /XHeight 447 0.564 G 0 g >> q /Resources<< 65.906 4.894 TD stream /Meta145 Do /Subtype /Form q /Resources<< /Meta414 Do Q 98.843 5.203 TD >> >> q 0 G 1 i 1 i /ProcSet[/PDF] /FormType 1 Q 231 0 obj /FormType 1 /Length 54 endobj << q 1.005 0 0 1.007 102.382 653.441 cm /Matrix [1 0 0 1 0 0] >> >> 0 g /Font << 0 g 722.699 726.464 l 1 i endobj /Matrix [1 0 0 1 0 0] 1 i endobj Q /Type /XObject q /F1 7 0 R /FormType 1 Q q 22.478 4.894 TD /BBox [0 0 88.214 16.44] q 20.21 5.203 TD Q /Meta222 236 0 R q /ProcSet[/PDF] << >> Q /Subtype /Form endstream /Meta312 Do /BBox [0 0 88.214 16.44] Q Explanation: let the number be n. then we can express division in 2 ways. /Resources<< /FormType 1 Q 672.261 799.486 m Q 436 0 obj 0 G /Meta420 Do >> 0 5.203 TD << /XObject << /BBox [0 0 88.214 16.44] 0 w /BBox [0 0 15.59 16.44] /Resources<< 0.564 G q /Meta114 Do /Meta57 Do 0 g >> Q /Subtype /Form 1 i q /Type /XObject endobj /Length 16 q endobj 1.502 24.649 TD Q /Meta58 Do 0.564 G /BBox [0 0 15.59 29.168] /FormType 1 endstream /Resources<< q >> 1.007 0 0 1.006 411.035 437.384 cm /Subtype /Form If LtitnS6S . stream /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q /ProcSet[/PDF/Text] q 0.564 G 1 i q /ProcSet[/PDF/Text] 1 i /ProcSet[/PDF/Text] /Subtype /Form To find: The. q 1.014 0 0 1.006 391.462 437.384 cm /ProcSet[/PDF] 0 G /Meta394 Do 0 5.203 TD /Meta414 430 0 R /Font << /FormType 1 /Matrix [1 0 0 1 0 0] endobj q Q 1 i /Meta304 Do 0.564 G (5) Tj 1.007 0 0 1.007 271.012 849.172 cm /ColorSpace [/Indexed /DeviceGray 1 ] /Font << << stream >> BT /Resources<< << 0.737 w /Type /XObject Q There were x cookies at the beginning of a party. q 174.501 5.203 TD q /Matrix [1 0 0 1 0 0] (C\)) Tj endobj endstream 1.007 0 0 1.007 130.989 583.429 cm << /FormType 1 0 g /Subtype /Form q /Resources<< /Meta271 285 0 R /Subtype /Form 20.21 5.203 TD /BBox [0 0 17.177 16.44] >> /Type /XObject >> q Phrase. >> q /Font << 1.007 0 0 1.007 551.058 277.035 cm Q >> /Meta422 438 0 R endobj /FormType 1 Q Q 0 G /F3 17 0 R BT 293 0 obj >> q Q 0 g /Matrix [1 0 0 1 0 0] >> /Length 12 0 G /FormType 1 0 g /BBox [0 0 639.552 16.44] /Type /XObject 317 0 obj /F4 12.131 Tf /Resources<< /Matrix [1 0 0 1 0 0] /Subtype /Form /Subtype /Form /Resources<< /Matrix [1 0 0 1 0 0] 0.68 Tc 1.502 5.203 TD 417 0 obj << 549.694 0 0 16.469 0 -0.0283 cm 0.369 Tc /Meta291 305 0 R Q >> Q /Length 16 Cho)18(ose the one alternative that best complet)19(es the statement or answers the question)15(.)] 0 G 0.369 Tc /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 654.946 799.486 cm 0 g endstream /Matrix [1 0 0 1 0 0] /Subtype /Form stream Q q /FormType 1 if the solution of an equation is x=-2, what could the original equation be? Q /Subtype /Form Q << stream 0 g 0 G >> q q /FormType 1 Q Q /BBox [0 0 534.67 16.44] /Font << Q stream /Subtype /Form /Matrix [1 0 0 1 0 0] q 0.524 Tc /Matrix [1 0 0 1 0 0] /BBox [0 0 17.177 16.44] 52.412 5.203 TD /BBox [0 0 88.214 16.44] << Q /BBox [0 0 15.59 16.44] Q BT 1.007 0 0 1.007 551.058 703.126 cm >> << endstream endstream /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] /Meta89 Do 0 g >> 1.007 0 0 1.007 551.058 277.035 cm /F2 12.131 Tf << /Subtype /Form q endobj /Descent -277 endobj Q /Meta210 Do /ProcSet[/PDF/Text] ET /FormType 1 /F3 17 0 R << >> 0 g Q 0 g q endobj Q /Matrix [1 0 0 1 0 0] >> BT /Subtype /Form 0 g 1 i /Meta355 Do /Matrix [1 0 0 1 0 0] Q /StemH 77 << << endobj Solution. >> /ProcSet[/PDF/Text] >> q >> >> q q ET /FormType 1 >> endobj endstream /Meta99 Do [(thir)17(te)15(en)] TJ 1.005 0 0 1.007 102.382 473.519 cm Q endstream Q /BBox [0 0 88.214 16.44] /Meta214 Do /Length 16 /FormType 1 q Q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 415 0 obj /BBox [0 0 88.214 35.886] << q << /FormType 1 /Resources<< q 0.458 0 0 RG 207 0 obj Q /Length 69 1.014 0 0 1.007 391.462 383.934 cm endstream /Type /XObject /Meta228 242 0 R Q Q 1.007 0 0 1.006 130.989 437.384 cm /Resources<< 1.007 0 0 1.007 654.946 599.991 cm 0.297 Tc /Resources<< 0 w /ProcSet[/PDF/Text] ET /Length 59 endobj /BBox [0 0 639.552 16.44] q 0 5.203 TD /Type /XObject /BBox [0 0 15.59 29.168] 1 i Q /Matrix [1 0 0 1 0 0] q /ProcSet[/PDF] /Meta103 117 0 R Q /BBox [0 0 88.214 16.44] 0.178 Tc ET BT /ProcSet[/PDF/Text] << ET 1.007 0 0 1.007 271.012 277.035 cm endobj >> << 1.007 0 0 1.007 67.753 473.519 cm /Type /XObject Q /Subtype /Form Q endobj 0 G endobj /Matrix [1 0 0 1 0 0] BT Three times a number equals fifteen 3. stream 0 g 1 g a Question /Length 68 BT Q /Meta382 396 0 R 0.458 0 0 RG /Matrix [1 0 0 1 0 0] S /Matrix [1 0 0 1 0 0] stream q /Meta334 348 0 R /Length 69 << /Meta203 Do >> Q q endstream This site is using cookies under cookie policy . endobj /Meta300 314 0 R /Font << 0.458 0 0 RG << /Meta261 Do 0 g Q q q q /Meta281 Do /BBox [0 0 15.59 16.44] 0 G 0 g /Meta340 354 0 R >> endstream Q 16.469 5.203 TD /Subtype /Form q /Subtype /Form ET 0.564 G /FormType 1 /ProcSet[/PDF] 0.737 w q /Type /XObject 0.564 G 0.737 w /ProcSet[/PDF/Text] ET Q /ProcSet[/PDF] q /Resources<< /BBox [0 0 88.214 16.44] /FormType 1 stream 6 0 obj Q stream endobj >> >> 27.693 5.203 TD /Type /XObject q 135 0 obj q /FormType 1 /ProcSet[/PDF] Q /Resources<< endstream /Meta350 364 0 R /FormType 1 q You can also contact the clerk of court in the county you received the ticket. q /BBox [0 0 88.214 35.886] endobj -0.486 Tw >> 0.564 G Q /Matrix [1 0 0 1 0 0] stream /Length 16 /Font << >> /Matrix [1 0 0 1 0 0] >> /ProcSet[/PDF/Text] BT (viii) A number divided by 8 gives 7. q 0 g 0.51 Tc /Matrix [1 0 0 1 0 0] 1.014 0 0 1.007 531.485 523.204 cm >> << /Meta234 248 0 R q 407 0 obj q Q /Resources<< q q /Font << q >> /FormType 1 /BBox [0 0 15.59 16.44] 0 G Q ET Aktual'nye voprosy Vol 10, No 3 (2020) Q Q 1.007 0 0 1.007 271.012 383.934 cm endobj Formula - How to Calculate Percentage Decrease. 0 G /Matrix [1 0 0 1 0 0] /Font << /Subtype /Form q q /ProcSet[/PDF] /Resources<< >> << q q Q /Meta314 Do >> 1.007 0 0 1.007 271.012 383.934 cm /FormType 1 /Font << /Matrix [1 0 0 1 0 0] 0.786 Tc stream 0 g /ProcSet[/PDF] endstream >> /ProcSet[/PDF] 0.458 0 0 RG stream BT /F3 12.131 Tf << q /F3 12.131 Tf /Type /XObject Q >> q endobj endstream q 1.007 0 0 1.007 130.989 330.484 cm >> 1.005 0 0 1.007 79.798 846.161 cm Q /BBox [0 0 534.67 16.44] /F3 12.131 Tf >> q /Type /XObject /FormType 1 << 0 g stream >> Q /Type /XObject 0 w /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /BBox [0 0 15.59 29.168] >> q /Meta249 Do q /BBox [0 0 88.214 16.44] /Resources<< /Subtype /Form q /Meta389 Do >> q 0 g 0.564 G 220.931 4.894 TD q /ProcSet[/PDF/Text] q q Q /Matrix [1 0 0 1 0 0] >> BT endstream /Type /XObject << The value of k is: (b) 3 (d) 0 (a) 4 (c) -4 TL ing:, 1)take a graph and draw two perpendicular lines to obtain four uadrants 2)draw any object using straight line 3) write the coordinates of each point o [(1)-25(0\))] TJ q /Meta381 395 0 R 1 i (x) Tj Q /Length 60 /BBox [0 0 88.214 16.44] 141 0 obj 35,000 worksheets, games, and lesson plans, Spanish-English dictionary, translator, and learning, **Note: You could choose any variable you want, to represent the numbers. 0.458 0 0 RG >> BT Q /Resources<< /Meta147 161 0 R endobj /Meta291 Do /Meta344 358 0 R (D) Tj /F3 12.131 Tf /Subtype /Form stream /Matrix [1 0 0 1 0 0] Q endstream >> 0.838 Tc endstream /Meta215 229 0 R endstream Q Q 1.007 0 0 1.007 130.989 330.484 cm 33.704 5.203 TD q Q /Type /XObject q /Resources<< [( times )15(a numb)22(er and )] TJ >> /Font << 0.68 Tc /Type /XObject /Meta267 281 0 R << 1 g 1.007 0 0 1.007 551.058 383.934 cm /Type /XObject endobj Q Q 0 g /Meta307 321 0 R /Subtype /Form << 0 39.216 TD 1.007 0 0 1.007 271.012 849.172 cm /ProcSet[/PDF] /Meta427 Do Q << 1 i q /ProcSet[/PDF/Text] >> 1 i stream /Meta329 343 0 R endobj /Subtype /Form q 62 0 obj 0.564 G /FormType 1 Q >> q 1 i /FormType 1 ET /BBox [0 0 15.59 16.44] BT /Type /XObject endobj Q /ProcSet[/PDF] 0.458 0 0 RG ET stream /Length 69 Answer (1 of 8): Solution: let the number be x. << /Resources<< /Subtype /Form Q /Meta29 42 0 R /FormType 1 Q /F1 12.131 Tf /Length 69 /Length 59 endstream >> 1.502 5.203 TD /Type /XObject /Resources<< q /Resources<< 0 g 1 g /FormType 1 >> /F3 12.131 Tf /F3 17 0 R q /Length 58 /Meta319 333 0 R 0.564 G /Meta115 Do 0 g 0.737 w /Meta189 203 0 R 1 i 115 0 obj /Resources<< 2 See answers pharry1800 pharry1800 Answer: 2n-58 Step-by-step explanation: olivbreadh olivbreadh Answer: 2x-116 or 2(x-58) Step-by-step explanation: Transalate it to numbers and operations: => 2(x-58) => 2x-116 You won't have a solid number since its not an equation. /Subtype /Form /Matrix [1 0 0 1 0 0] /Meta71 Do Q 1.007 0 0 1.007 411.035 277.035 cm /Resources<< 25.454 5.203 TD Q 0 G /BBox [0 0 15.59 29.168] 108 0 obj /Matrix [1 0 0 1 0 0] /Meta140 154 0 R /Length 16 257 0 obj /FormType 1 1.007 0 0 1.007 130.989 583.429 cm << 0.31 Tc >> 0 G >> /Meta270 284 0 R q /Resources<< BT /F4 36 0 R /F3 12.131 Tf /Length 16 q 99 0 obj /Type /XObject 0.271 Tc (6\)) Tj ( decreased by ) Tj /ProcSet[/PDF/Text] /Subtype /Form Q >> /F3 17 0 R >> q << /I0 51 0 R /Type /XObject >> 0 g q stream q You can specify conditions of storing and accessing cookies in your browser. /Meta64 78 0 R /Subtype /Form 1 i 1.005 0 0 1.007 79.798 829.599 cm /ProcSet[/PDF/Text] 0.838 Tc q /Type /XObject /FormType 1 1.005 0 0 1.007 102.382 293.596 cm /ProcSet[/PDF/Text] /Type /XObject >> /BBox [0 0 88.214 16.44] ET Q /Subtype /Form q 0 g /FormType 1 q /Length 12 >> 3.742 5.203 TD endstream 218 0 obj /FormType 1 endobj /Resources<< >> Q Q q /F3 17 0 R << q >> /Resources<< q Q /Meta9 20 0 R Q 1.007 0 0 1.006 411.035 690.329 cm /Matrix [1 0 0 1 0 0] /F4 36 0 R q Q q Q 1 i 1 i 365 0 obj /Matrix [1 0 0 1 0 0] 0 G Q /Type /XObject 1 i BT Q /FormType 1 1 i ET 445 0 obj /Meta56 Do >> /Resources<< 1.007 0 0 1.007 45.168 829.599 cm q >> /Type /XObject /LastChar 121 /Matrix [1 0 0 1 0 0] /Leading 150 Q endstream q << /Meta208 222 0 R 0 g /FormType 1 >> BT /F4 36 0 R << /FormType 1 q /FormType 1 /Subtype /Form 0.458 0 0 RG << 0.175 Tc stream >> /Resources<< Q Q /ProcSet[/PDF/Text] /Resources<< q /Matrix [1 0 0 1 0 0] (-) Tj 30.699 5.203 TD q endstream q /Resources<< 139 0 obj Step 1/1. >> 17.234 5.203 TD << /Font << (-4) Tj q /Type /XObject q Q 0 w BT 376 0 obj endobj /F3 12.131 Tf q ET /Meta428 444 0 R /F4 12.131 Tf << endstream q 1 i q /Matrix [1 0 0 1 0 0] /BBox [0 0 30.642 16.44] /BBox [0 0 88.214 35.886] Expert Answer. 0 g /Type /XObject 58 0 obj /Type /XObject /Matrix [1 0 0 1 0 0] q /Resources<< Q >> /F3 12.131 Tf /BBox [0 0 88.214 16.44] q 4 0 R 1.007 0 0 1.007 271.012 450.181 cm /Matrix [1 0 0 1 0 0] 1 i q n 11 or n 11. (C\)) Tj Q ET 32.201 5.203 TD 1 g 1 i /F3 12.131 Tf Q /Meta45 59 0 R q /ProcSet[/PDF/Text] 1 i q stream /FirstChar 32 q /F3 17 0 R BT endstream 0 w 1.007 0 0 1.007 551.058 383.934 cm BT 0.458 0 0 RG That was 1/8 of the points that he scored /F3 17 0 R endstream /Meta403 419 0 R /FormType 1 (D\)) Tj /Length 54 endobj >> 0 G q /Font << /Font << /BBox [0 0 30.642 16.44] /Meta199 Do Q q /BBox [0 0 673.937 68.796] /Subtype /Form Twice a number decreased by ten is greater than 24. q BT ET >> /F3 17 0 R 1.007 0 0 1.007 411.035 277.035 cm endstream /F3 17 0 R q << << endstream ET endobj /Meta70 84 0 R Q /ProcSet[/PDF/Text] << << >> New questions in Mathematics >> endstream 0 G 1 i q Q 1 g Q q /BBox [0 0 88.214 16.44] /Length 294 0 G /BBox [0 0 15.59 16.44] >> /Length 16 0 5.203 TD /Subtype /Form /Subtype /Form q /BBox [0 0 15.59 16.44] stream /Type /XObject /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] 1 g /Size 447 BT /Resources<< 1 g q /Meta327 Do << /Matrix [1 0 0 1 0 0] Q /Meta331 Do 0 w 1 i /Font << /ProcSet[/PDF/Text] >> /Resources<< 250 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 g /ProcSet[/PDF] 0 4.894 TD /Length 16 Q q q >> 1 g /Subtype /Form /F3 17 0 R 0.382 Tc /FormType 1 endstream q ( x) Tj >> >> 1.014 0 0 1.007 531.485 583.429 cm /BBox [0 0 639.552 16.44] << /Subtype /Form >> q Q Q endstream >> /Subtype /Form /I0 Do /Font << /Matrix [1 0 0 1 0 0] stream 442 0 obj Q /F3 12.131 Tf ET >> 1.007 0 0 1.007 654.946 347.046 cm /F3 17 0 R << Q The results found were expressed mainly through tables and graphs as the main resources of the statistical language. << 0 G /Matrix [1 0 0 1 0 0] /Meta0 Do /Resources<< Q endstream ET endstream /BBox [0 0 88.214 16.44] 295 0 obj /Flags 32 >> /BBox [0 0 15.59 16.44] Q << q endstream The quotient of a seven and a number 9. 1.007 0 0 1.007 411.035 583.429 cm /Subtype /Form << << 0 G /BBox [0 0 30.642 16.44] endobj 0.737 w /Length 16 >> endobj 1.007 0 0 1.007 67.753 599.991 cm q Q /Matrix [1 0 0 1 0 0] Q /Meta66 80 0 R /F3 12.131 Tf /ProcSet[/PDF/Text] endobj q 1 i /Length 16 1 i >> ET 156 0 obj 0 G /F3 17 0 R ET Q stream /Type /XObject BT /F3 12.131 Tf 1 i (2) Tj 1.007 0 0 1.007 67.753 726.464 cm q /BBox [0 0 534.67 16.44] 1 i endstream q /Font << Q Check out a sample Q&A here. /Matrix [1 0 0 1 0 0] /Resources<< q >> q q 1 i /Subtype /Form endobj 0 g (-20) Tj 0 G stream >> 0 w 0 g stream /Font << /ProcSet[/PDF] endobj Q Q (5\)) Tj /Resources<< Q 0 5.203 TD /F3 12.131 Tf Q ET Q /F4 36 0 R 9.723 5.336 TD 3.742 5.203 TD 58 decreased by twice Gails age. 0 5.203 TD /Type /XObject q (+) Tj /BBox [0 0 15.59 29.168] >> q /BBox [0 0 88.214 35.886] /Length 16 endstream Q 1.005 0 0 1.007 102.382 872.509 cm Q >> /Type /XObject /Type /XObject q 1 i /F3 12.131 Tf >> q >> 1.502 5.203 TD (5) Tj /Subtype /Form endstream /F4 12.131 Tf 1 i Q >> q /Type /XObject /Subtype /Form /Subtype /Form /BBox [0 0 534.67 16.44] /Meta157 Do BT 0 w << endstream /ProcSet[/PDF/Text] >> Q 0 g 0.458 0 0 RG /FontName /PalatinoLinotype-Roman You could call them. /Resources<< /ProcSet[/PDF/Text] /Meta147 Do 0.458 0 0 RG 91 0 obj 0 w 271 0 obj 0 G /FormType 1 Q /Type /XObject 121 0 obj >> endobj q endstream endstream << ET 0.564 G 1 i /Type /XObject q 0 g >> q 0 g (1\)) Tj Q 1.007 0 0 1.007 271.012 583.429 cm endstream 0.155 Tc stream /Resources<< endobj /Meta416 Do >> /Length 58 /Meta365 379 0 R BT endobj 38.948 5.203 TD ET /Subtype /Form /Meta268 282 0 R >> 0 G stream endobj q /ProcSet[/PDF/Text] endobj /Length 16 /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] << Q q /Meta305 319 0 R >> >> 1 i BT 1 i /FormType 1 << 405 0 obj q >> q 1 i /Meta244 258 0 R /F3 17 0 R /Subtype /Form /Font << Q q q Q /BBox [0 0 88.214 16.44] endstream q endstream /Resources<< << /FormType 1 245 0 obj Q /BBox [0 0 88.214 16.44] stream stream >> Q endstream BT q 1.007 0 0 1.007 271.012 523.204 cm /XObject << /Type /XObject /BBox [0 0 15.59 16.44] /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] BT /Type /XObject /Length 60 stream endstream q endstream q /Type /XObject Q /Meta233 247 0 R 6.746 5.336 TD q 1.007 0 0 1.007 551.058 383.934 cm /Matrix [1 0 0 1 0 0] 284 0 obj >> endstream 0 G 0 g /Type /XObject /ProcSet[/PDF/Text] stream endobj stream Q S /Meta318 332 0 R /BBox [0 0 15.59 16.44] endobj stream ET stream /Meta391 Do /Type /XObject /Meta404 420 0 R Q stream /Type /XObject /Type /FontDescriptor /Subtype /Form /Resources<< 1 i 0 w stream << 0.838 Tc /Matrix [1 0 0 1 0 0] 0 G BT /BBox [0 0 88.214 16.44] q /F3 12.131 Tf q /Type /XObject 0 5.203 TD << /Meta294 308 0 R /F1 12.131 Tf stream Q 31 0 obj /Subtype /Form BT 100 0 obj >> /FormType 1 0 g 0 G 0 G /ProcSet[/PDF] 0.737 w /ProcSet[/PDF] /Font << 1 i /Type /XObject Q Q >> 1.014 0 0 1.007 531.485 383.934 cm Q endstream q /Contents [399 0 R] Let x be a number. /Length 73 stream endobj 1.005 0 0 1.006 45.168 879.284 cm Q /Font << Q Q 1 i /Meta155 Do /BBox [0 0 15.59 16.44] /F1 12.131 Tf /Meta206 Do endstream endstream /Meta377 Do 1.007 0 0 1.007 411.035 277.035 cm /Resources<< (x) Tj /ProcSet[/PDF] /ProcSet[/PDF] Q >> q /Meta237 251 0 R /Length 54 0 5.203 TD Q 1.007 0 0 1.007 551.058 703.126 cm /Resources<< q 324 0 obj /ProcSet[/PDF] /BBox [0 0 30.642 16.44] >> /MaxWidth 1453 /F3 17 0 R endstream /Matrix [1 0 0 1 0 0] >> Q >> q 0 G endobj BT /Type /XObject /F4 36 0 R 0 G (A\)) Tj q endstream /Type /XObject 0.51 Tc 0 g >> /ProcSet[/PDF/Text] /ProcSet[/PDF] /Length 59 /Matrix [1 0 0 1 0 0] BT ET /Meta175 189 0 R /FormType 1 /Meta123 137 0 R /FormType 1 endstream /FormType 1 /Length 69 /Producer (PDF-XChange 4.0.0186.0000 \(Windows\)) q /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] 221 0 obj q /FormType 1 endobj 1 of this study. /Meta248 262 0 R q 1.005 0 0 1.006 45.168 879.284 cm 0 G q /F3 17 0 R /Subtype /Form Q /FormType 1 /Meta97 Do Q /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] 0.486 Tc /Meta404 Do 20.21 5.203 TD Q /FormType 1 Q >> q Get link; Facebook; Twitter; (-9) Tj >> /Matrix [1 0 0 1 0 0] << endstream /Meta62 76 0 R 20.975 5.336 TD endobj /Matrix [1 0 0 1 0 0] /F4 12.131 Tf << 0.737 w 0 g /FormType 1 0.458 0 0 RG << 214 0 obj /Length 69 /Resources<< 241 0 obj 0 g /Type /XObject /Meta11 Do 0.564 G endstream /ProcSet[/PDF] q BT q /Meta332 Do << endobj /Length 59 q Q Q 0 g /Meta108 Do /Font << 0.564 G 0.296 Tc q 1 g q 0.297 Tc Q /Type /XObject /BBox [0 0 15.59 16.44] 283 0 obj Q 1 i /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Length 12 q 0 G q 0.458 0 0 RG /Subtype /Form S BT 433 0 obj /Length 69 0 g /Type /XObject (-) Tj /Meta130 Do q /FormType 1 /Subtype /Form 0.738 Tc q Q /Matrix [1 0 0 1 0 0] Q /Subtype /Form /F3 12.131 Tf endobj /BBox [0 0 15.59 16.44] /FormType 1 >> Q 408 0 obj /Type /XObject Mat << Q BT >> Q Q 0.241 Tc endobj /Type /XObject /Length 69 << q 0 G Q /FormType 1 1 i /Length 16 q << (C) Tj 1 i 0 w (-) Tj Q /Length 13 endobj BT /BBox [0 0 88.214 16.44] >> /Type /XObject (4) Tj << /Meta415 Do Q endobj Diabetes, also known as diabetes mellitus, is a group of common endocrine diseases characterized by sustained high blood sugar levels. /BBox [0 0 88.214 16.44] Q >> q /FormType 1 349 0 obj >> 332 0 obj 1 g ET Q Q >> endobj /Resources<< /Meta224 238 0 R Q /Meta254 268 0 R >> q << 0 g q Q /BBox [0 0 88.214 16.44] /F3 12.131 Tf 1 i /CapHeight 476 (B\)) Tj /FormType 1 26.957 5.203 TD Q q BT /Resources<< /F1 12.131 Tf Q /Meta354 368 0 R q /Matrix [1 0 0 1 0 0] >> Q Q 1 i Q 0 G Q Q >> /Subtype /Form 0.458 0 0 RG 0 20.154 m Q endstream >> /F1 12.131 Tf 2. Q 1.007 0 0 1.007 271.012 383.934 cm /Type /XObject /Meta75 Do /Resources<< Q q 0.737 w 1 i q 1 g Q << Q /F3 12.131 Tf /FormType 1 /Length 65 1 i /Type /XObject /Resources<< 1 i /Type /XObject q /ProcSet[/PDF] 0 g >> /ProcSet[/PDF/Text] 1 i q >> /Resources<< /F3 12.131 Tf endstream /ProcSet[/PDF] (-20) Tj
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